XxmathguyxX

so when you copy paste on a thing called alcumus is gives a $ sign

scroll up and you will see a question like this. Hopefully that helps you!

wow.. a much easier way!

\(5x^2-11x+4=0\)

\(x_{1,\:2}=\frac{-\left(-11\right)\pm \sqrt{\left(-11\right)^2-4\cdot \:5\cdot \:4}}{2\cdot \:5}\)

\(x_{1,\:2}=\frac{-\left(-11\right)\pm \sqrt{41}}{2\cdot \:5}\)

\(x_1=\frac{-\left(-11\right)+\sqrt{41}}{2\cdot \:5},\:x_2=\frac{-\left(-11\right)-\sqrt{41}}{2\cdot \:5}\)

\(x=\frac{11+\sqrt{41}}{10},\:x=\frac{11-\sqrt{41}}{10}\)

1/(a+1)=\(\frac{21-\sqrt{41}}{40}\)

1/(b+1)=\(\frac{21+\sqrt41}{40}\)

total=\(\frac{21}{20}\)

mhm Guest is correct, so next time you come across these type of problems, you multiple the top and the botttom by the same amount to get to your answer.

Thank you!

for the first box, 4 choices

for the second box, 3 choices

for the third box, 2 choices

4*3*2=24

hm....

you're right...

that was a much easier way thank you!

\(458-98=360\)

\(360\div45=8\)

so 8 hours of labor!

um..... I can't tell apart letters on this thing, can you plz write a little clearer?