How many ways are there to put 4 distinguishable balls into \(3\) indistinguishable boxes?
for the first box, 4 choices
for the second box, 3 choices
for the third box, 2 choices
4*3*2=24
How many ways are there to put 4 distinguishable balls into 3 indistinguishable boxes?
can the boxes be empty. I will asume they can
Everything is indsitinguishable so...
4,0,0
3,1,0
2,2,0
2,1,1
that is it. 4 ways.
+363 
