\(2x(x + 10) = -50\)
\(2x^2+20x=-50\)
\(2x^2+20x+50=-50+50\)
\(2x^2+20x+50=0\)
\(x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:2\cdot \:50}}{2\cdot \:2}\)
\(x_{1,\:2}=\frac{-20\pm \sqrt{0}}{2\cdot \:2}\)
\(x=\frac{-20}{2\cdot \:2}\)
\(x=-5\)
so the value is -5
so -5!
hope this helps!,
XxmathguyxX