zacismyname

Yes there are a number of ways.

One is to simply use "^", which indicates exponents. Eg. x^2 = x²

Another is to use any of the three formula/calculation applications on the bottom-most header bar. (eg. LaTeX, Math Formula, Calculation). These all use "^" to indicate powers, though they will be formatted like this:

$${{\mathtt{x}}}^{{\mathtt{2}}} = {\mathtt{4}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{2}}\\
{\mathtt{x}} = {\mathtt{2}}\\
\end{array} \right\}$$....................$${{\mathtt{x}}}^{{\mathtt{2}}} = {\mathtt{4}}$$.............$$x^2=4$$

Lastly you can go to the insert tab, then go to symbols, and there you will find some limited exponents, as well as a number of other useful symbols.

Assuming no rate of acceleration etc...

.025 feet/minute (multiply  by 40)

1 feet/ 40 minutes (multiply by 5)

5 feet / 200 minutes (=3 hours 20 minutes)

The chance Esmerelda gets a puppy is 27%, while the chance of Randy not getting a new puppy is 40%.

Since we need both these outcomes to be true . . . multiply the two percentages.

The probability that Esmerelda gets a new puppy and Randy does not: (27%*40%) = P(10.8%)

I believe googol is 1 with 100 0's. So in that case it's:

$$1\times10^{100}$$

$$-2(x+5) -7(x-2)$$ ......Expand

$$-2x -10 -7x +14$$.......Group like terms

$$-9x + 4$$

Using the old analogue of apples and bannanas:

We have 6 apples, half an apple, and a bannana

So we have 6.5 apples and a bannana

Since it's actually units, not apples, it is just 6.5

0.5 + 6 + g -----> 6.5 + g

Thanks 

You would do the exponent first. They come after brackets but before multiplication, division etc. (PEDMAS)

Well it depends what you are asked to find . . .

The intercept/gradient form is y = mx + b, where m = gradient and b = the y-intercept

so y = 2*(x + 2)     ------>    y = 2x + 4

so m = 2

the y-intercept = 4

To find the x-intercept we can make y = 0 . . .

0 = 2x + 4

2x = -4

x = -4/2 = -2

the x-intercept = -2

If you are asked to graph it, then start on a point you know (the y-intercept), which has the coordinates of (0,4). For your other point you could either use your x-intercept or another point based on your gradient. 

We know that m = rise/run. 2 can be written as 2/1, where for every positive unit moved on the run (x), it moves 2 on the rise (y)

So starting at (0,4) and moving accross 1 on the x we rise 2 on the y. So (0+1,4+2) = (1,6)

So you could graph it using the points (0,4) and (1,6), drawing a continuous line though them and continuing on indefinately in both directions.

Sorry if I am being too long winded/confusing. Here is it graphed so you can visualise it.

The quadratic formula is ususally an option but here I would probably do this:

$$8y^2 + 26y + 15$$   

( Note that 8 does not go easily into the other terms, making factorising by straight up removing the 8 out of the question. Instead we can look at the product of 8 and 15, with the intention of splitting 25 up into 2 terms which can then be factorised. What 2 numbers add to make 26 and multiply to make (8*15) 120? 6 and 20)

$$8y^2 + 6y + 20y + 15$$

( Now we factorise in pairs)

$$2y(4y + 3) + 5(4y + 3)$$

$$(2y + 5)(4y + 3)$$

YAY :)

Just to check.....

$$(2y + 5)(4y + 3)$$

$$(2y\times{4y}) + (2y\times{3}) + (5\times{4y}) + (5\times{3})$$  (FOIL)

$$8y^2 + 6y + 20y + 15$$

$$8y^2 + 26y + 15$$