+980 Well it depends what you are asked to find . . .
The intercept/gradient form is y = mx + b, where m = gradient and b = the y-intercept
so y = 2*(x + 2) ------> y = 2x + 4
so m = 2
the y-intercept = 4
To find the x-intercept we can make y = 0 . . .
0 = 2x + 4
2x = -4
x = -4/2 = -2
the x-intercept = -2
If you are asked to graph it, then start on a point you know (the y-intercept), which has the coordinates of (0,4). For your other point you could either use your x-intercept or another point based on your gradient.
We know that m = rise/run. 2 can be written as 2/1, where for every positive unit moved on the run (x), it moves 2 on the rise (y)
So starting at (0,4) and moving accross 1 on the x we rise 2 on the y. So (0+1,4+2) = (1,6)
So you could graph it using the points (0,4) and (1,6), drawing a continuous line though them and continuing on indefinately in both directions.
Sorry if I am being too long winded/confusing. Here is it graphed so you can visualise it.
+980 Well it depends what you are asked to find . . .
The intercept/gradient form is y = mx + b, where m = gradient and b = the y-intercept
so y = 2*(x + 2) ------> y = 2x + 4
so m = 2
the y-intercept = 4
To find the x-intercept we can make y = 0 . . .
0 = 2x + 4
2x = -4
x = -4/2 = -2
the x-intercept = -2
If you are asked to graph it, then start on a point you know (the y-intercept), which has the coordinates of (0,4). For your other point you could either use your x-intercept or another point based on your gradient.
We know that m = rise/run. 2 can be written as 2/1, where for every positive unit moved on the run (x), it moves 2 on the rise (y)
So starting at (0,4) and moving accross 1 on the x we rise 2 on the y. So (0+1,4+2) = (1,6)
So you could graph it using the points (0,4) and (1,6), drawing a continuous line though them and continuing on indefinately in both directions.
Sorry if I am being too long winded/confusing. Here is it graphed so you can visualise it.
