Since we can position the vectors in any convenient manner....Let one vector = ( 10, 0) and the other = (0, 5)
This will allow for an easy way to calculate the angle between the resultant and the 10N vector
The resultant = √ [10^2 + 5^2 ] = √125 = 5√5 N
The angle between the 10N vector and the resultant =
tan θ = 5/10
arctan (5/10) = θ ≈ 26.6°
