CPhill

Let Jo's amount be x

Let Lou's be 2x

And let Sherry's amount be x - 11

And together they all have $89....so....

x + 2x + x - 11  = 89    simplify

4x - 11  = 89     add 11 to both sides

4x = 100    divide by 4 on both sides

x = 25

And Lou has 2x = 2(25)  = $50

Thanks for that nice answer, saseflower....!!!

This is just all the possible sets that could be formed by choosing any 6 of 26 people.....this is given by

C(26, 6)  = 230,230 possible sets....!!!

Welcome aboard......!!!

∞ x ∞ = ∞

∞ + ∞  = ∞

∞ - ∞ = ∞

As you may have noticed, infinity doesn't folllow the "normal" math rules. This because it's a concept rather than a number.

To see the last one above.....note that if I took away all the even integers {an infinite set in themselves} from the set of integers on the number line {another infinite set} , I would have the set of all odd integers left ...... {another infinite set}...!!!!!

(50 / 180) x pi = ( 5pi / 18 ) rads

A relation only.....it fails the vertical line test......so it's not a function.....every x value, except 0, is associated with two different y values....to be a function, no single x value can be associated with two different y's

-13 and 11

How about 12/72  ???   {which = 1/6 }

Let's call this function z

So

z = (52 - 3x^2 - 4y^2)^(1/2)  .... so.....

z_x = (1/2)(52 - 3x^2 - 4y^2)^(-1/2) * ∂/∂x (52 - 3x^2 - 4y^2) =

(1/2) (52 - 3x^2 - 4y^2)^(-1/2) * (-6x) =

(-3x)(52 - 3x^2 - 4y^2)^(-1/2)

Remember....we're differetiating with respect to x, so any "y" terms are treated as constants when taking their derivatives.....