Let's call this function z
So
z = (52 - 3x^2 - 4y^2)^(1/2) .... so.....
zx = (1/2)(52 - 3x^2 - 4y^2)^(-1/2) * ∂/∂x (52 - 3x^2 - 4y^2) =
(1/2) (52 - 3x^2 - 4y^2)^(-1/2) * (-6x) =
(-3x)(52 - 3x^2 - 4y^2)^(-1/2)
Remember....we're differetiating with respect to x, so any "y" terms are treated as constants when taking their derivatives.....
(52 - 3x2 -4y2)1/2
First derivative ---> (1/2)(52 - 3x2 - 4y2)-1/2(-6x - 8yy')
Let's call this function z
So
z = (52 - 3x^2 - 4y^2)^(1/2) .... so.....
zx = (1/2)(52 - 3x^2 - 4y^2)^(-1/2) * ∂/∂x (52 - 3x^2 - 4y^2) =
(1/2) (52 - 3x^2 - 4y^2)^(-1/2) * (-6x) =
(-3x)(52 - 3x^2 - 4y^2)^(-1/2)
Remember....we're differetiating with respect to x, so any "y" terms are treated as constants when taking their derivatives.....