2x^2+kx+6 = -x+4
2x^2+ x(k+1) +2 = 0
(2x+ )(x+ ) = 0 the only two factors which multiply to '2' are 1 and 2 or -1 and -2
(2x+1) (x+2) results in TWO values of x (-1/2 and -1)that would satisfy the system of equations...no good.
(2x+2)(x+1) = 0 would result in ONE values for 'x' : (-1) ....we want only ONE (Per the question)
so this would make k+1 = 4 or k=3
Multiply this out to get 2 x^2 + 4x +2 =0 so k+1 = 4 .... or k=3
(2x-2)(x-1) =0 works for only x =1
multiply it out 2x^2 -4x+2 means k+1 = -4 or k=-5
(2x-1)(x-2) has two solutions x = 1/2 and x= 2 no good
SO k = 3 or -5 results in only one solution for the system of equations.
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