What is the area under a chord with a central/arc angle of 125 and a radius of 8?
EDIT: I tried a few different methods and ended up with negative numbers. I really don't know what to do...
After reply 2:
EDIT: To clarify, I'm looking for are that is not a part of the traingle, but still part of the sector. Thank you Pavlov!
The chord line and the the two radii of 8 form a triangle of which one angle is 125 degrees and the other two are
27.5 degrees (must add to 180 degrees)
Draw a line of length 'h' perpindicular to the chord which bisects the 125 degree angle .
Now you have two equal triangles with angles of 90 125/2 and 27.5 degree angles
Now use law of sines to find 'h'
sin 90 /8 = sin 27.5 /h = sin 62.5/(1/2chord)
h = 3.694 and chord = 14.192
Then area of the triangle = 1/2 b h where b is the chord
Area = 1/2 (14.192)(3.694) = 26.22 units^2