Alan

You could also try a = (-97 + 49i)/5

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You will need a numerical approach.  For example:

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height = radius*tan(elevation)

radius = circumference /(2pi)

so radius = 29/(2pi) metres

$${\mathtt{height}} = {\frac{{\mathtt{29}}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{57}}^\circ\right)} \Rightarrow {\mathtt{height}} = {\mathtt{7.107\: \!236\: \!499\: \!870\: \!214\: \!1}}$$

height ≈ 7 metres

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Your conclusion is probably correct, but you should generate a better graph, as Dragonlance suggested.  If you provide the basic data, perhaps some kind soul on the website here will do it for you.

Also, it is usual to plot the independent variable (years of postgrad study) on the x-axis, and the dependent variable (yearly income) on the y-axis.

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Like so?

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tan(elevation) = altitude/horizontal distance, so:

tan(27°) = altitude/5.2miles

altitude = 5.2*tan(27°)

$${\mathtt{altitude}} = {\mathtt{5.2}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{27}}^\circ\right)} \Rightarrow {\mathtt{altitude}} = {\mathtt{2.649\: \!532\: \!337\: \!368\: \!8}}$$

altitude ≈ 2.6 miles  (4.2 km)

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(10 - 9 + 1)³ = 8

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cos(4x) → 1 - 8x² + 32x⁴/3 + ...

sin(3x) → 3x - 9x³/2 + ...

so: (1- cos(4x) + x*sin(3x))/x² → (1 - (1 -  8x² + 32x⁴/3 + ...) +x*(3x - 9x³/2 + ...))/x²

 → (8x² + 3x² + higher order terms in x)/x² →  11 + higher order terms in x

Hence in the limit as x → 0,  (1- cos(4x) + x*sin(3x))/x² → 11

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Maia, have a look at your private messages for a clarification.