tan(θ) = width/70 so
$${\mathtt{width}} = {\mathtt{70}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{54}}^\circ\right)} \Rightarrow {\mathtt{width}} = {\mathtt{96.346\: \!734\: \!432\: \!97}}$$
or width = 96 ft to the nearest foot.
(I've assumed the angle, θ, is between the line of sight to C and the line AB)
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