apsiganocj

a)

Step 1: suppose advin had x dollars at first. 

Step 2: make suitable equations that represents the actual scenario.

Step 3: find the value of x.

b) 

Total amount left= $44.

Total amount spent on books= $28+2/5 of his initial money.

Suppose advin had $x initially.

then, initial money= money left+ money spent

therefore, x=44+(28+(2/5)x ) 

x= 72+2x/5

x-2x/5 = 72

(5x-2x)/5 = 72

3x/5 = 72

x=72(5/3)

x= 120

Therefore,  Advin had total $120 at first.

Let the number of friend that Braydon have = x

Case 1: When he given 9 stickers to each friend.

Since he gave 9 stickers to each friend,

∴ Number of distributed stickers = 9x

While distributing 9 stickers to each friend he will be short for 69 stickers.

∴ The number of stickers Braydon actually have = 9x-69

Case 2 : When he given 4 stickers to each friend.

Since he gave 4 stickers to each friend,

∴ Number of distributed stickers = 4x

While distributing 4 stickers to each friend he will have 46 more tickets.

∴ The number of stickers Braydon actually have = 4x+46

Since Braydon have equal number of tickets in each case,

∴ 9x-69 = 4x+46

⇒ 9x-4x = 46+69

⇒ 5x = 115

⇒ x = 23

Hence there are 23 friends.

Number of stickers = 4x+46 = 4(23)+46 = 138

Now we know that there are 138 tickets in total and 23 friends.

Hence the number of tickets each friend will get such that no sticker remains = \({138 \over 23}{}{} = 6\)

Hence Braydon must given 6 tickets to each of his friend such that no sticker is left.

LCM(10,8) = 40
so 4 dogs, 5 8-buns
LCM(10,12) = 60
so 6 dogs, 5 12-buns

Assuming that Bob have x packets at first.

Morning sale: \( {1 \over 3}{}{}\)x + 2

After morning sale: x - (\( {1 \over 3}{}{}\)x + 2) = \({2 \over 3}{}{}\)x - 2

Afternoon sale: \( {1 \over 4}{}{}\)(\( {2 \over 3}{}{}\)x - 2) + 4 = \( {1 \over 6}{}{}\)x + \( {7 \over 2}{}{}\)
After afternoon sale: \( {2 \over 3}{}{}\)x - 2 - (\({1 \over 6}{}{}\)x + \( {7 \over 2}{}{}\)) = \( {x \over 2}{}{}\)-\( {11 \over 2}{}{}\)
\( {x \over 2}{}{}\)-\( {11 \over 2}{}{}\)= 8                            8 packets left

    x = 27

Use the conditions given to establish the equivalence 

relationship.

So the answer is 27 packets.

assume girls are x, boys are (15+x)

  1/4x - 1/5 (15+x) = 2

      1/4x - 1/5x = 5

                1/20x = 5

                       x = 100

15 + x = 115

sum = 115 + 100 = 215

John:  48 ÷ (1 - 3/5)

          = 48*5/2

          = 120 points 

Peter:  x - 1/3x = (120 - 48) + 18 

                    2/3x = 90

                         x = 135 points

John: 120 points

Peter: 135 points

white : x

 blue : y

  
   \( {24 - x \over 28 - x + 40 - y}{}{} = \)\({3\over 4}\)               \( {28 - x \over 68-x-y}\)\( = {3 \over 4}\)
{                                         {
{     \( {35 + y \over 10 + x 35 + y} = \)   \( {4 \over 5}\)         { \({35 + y\over 45 + x + y}\)\( = {4 \over 5}\)
 

{ 3 * 18 - 3x - 3y = 4 * 28 - 4x

{ 4 * 45 + 4x + 4y = 34 * 5 + 5y

   { x = 7

   { y = 33

So white : 7         blue :  33

let his salary be x 

         1288 + 2/5(x-1188)+ = x

           1288 + 2/5x -2576/5 = 3/4x

               1288 - 2576/5 = 7/20x

                          3864/5 = 7/20x

                              X=2208

On Tuesday he gathered the following carts;

17 + 19 + 30 = 66 

So he gathered a total of 66 carts on Monday 

On Tuesday he gathered the following carts;

30 + 25 + 41 = 96 

So he gathered a total of 96 carts on Tuesday. 
 

How many more carts did he gather up on Tuesday than he did on Monday? 
 

To answer this question, we simply need to minus what he gathered on Monday to what he gathered on Tuesday. 
 

So we have;

99 - 66 = 30

Therefore, he gathered 30 more carts on Tuesday than he did on Monday.

The total cost of vegetables is calculated as follows: 

Given: 

Pounds of frozen peas = 1.33

Pound of frozen corn = 0.375

Pounds of frozen broccoli = 2.5

Pounds of frozen carrots = 0.8

Cost per pound = $0.99

Solution:

Total cost = (Pounds of frozen peas + Pound of frozen corn + Pounds of frozen broccoli + Pounds of frozen carrots) * Cost per pound 

Total cost = (1.33 + 0.375 + 2.5 + 0.8) * $0.99

Total cost = 5.01 * $0.99 

Total cost = $4.96