There were some red, black and blue pens in a drawer. 1/3 of the pens were red and the number of black pens was 11 less than 1/2 of the number of red pens. If there were 284 blue pens, how many black pens were there in the drawer?

apsiganocj Aug 11, 2021

#1**+1 **

given data in

1/3rd of the pens are red.

number of black pens was 11 pens then 1/2 of the red pens.

There were total 284 blue pens.

To find number of black pens.

Assume that there are x red pen, y black pens, z blue pens, then

x = 1/3 (x + y + z)

z = 284 and y+11=1/2x

=> 3x = x + y + z ; z = 284 ; 2y+22=x

2x-y=284 x-2y=22

2(2y+22)-y=284

4y + 44 - y = 284

3y = 240

y = 80 x = 2 (80) + 22 = q82

x = 182

Thus there were total 80 black pens.

apsiganocj Aug 11, 2021