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Questions 18
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 #2
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Yes, this problem is really hard but it is solved.

 

Let,

      No of stickers Mark had =        'a'

      "    "    "           Nathan had =    'b'
      "    "    "           Owen had =      'c'

      Given,

              12.5% of Mark's stickers = 25% of Nathan's stickers

 

                   --->     a = 2 * b

 

                             a = 26    ---> b = a/2


No of stickers Owen had = 1/4th of Number of stickers Mark had

 

                              C = 1/4 * a

                             
                              a = 4c -->   C = a/4

a)   Ratio of all three is

                       a : b : c

                       a : a/2 : a/4

                       1 : 1/2 : 1/4

                    =    4 : 2 : 1

 

 

b)      Nathan gave 58 to Mark,

                then Owen had 1/5 of Mark's stickers

            -->           C = 1/5 * (a + 58)

                      -->    5c = a + 58
    we       (know)        a = 4c

                                  5c = 4c + 58

                                         C = 58

                                  --> a = 4 * 58 = 232

                                        b = a/2 = 232/2 = 116

        Total stickers = a + b + c

                              = 232 + 116 + 58

                              = 406

          
              Total = 406    

Oct 16, 2021