CalculatorUser

Tahnks!

Yes, this is correct!

your close!

 rearrange and subtitute in -3

(qx + ry + pz) + (rx + py + qz) - 3 = x + y + z

Oops I realized the next step is wrong! The problem may be harder than I thought!

-3 ( x + y + z) + (-3) (x + y + z) - 3 = x + y + z           (undistribute p + q + r because they = -3)
 

-3x - 3y - 3z -3x - 3y - 3z - 3 = x + y + z

-6x - 6y - 6z - 3 = x + y + z

7x + 7y + 7z = 3

answer is 3/7

I think so

You can ask for the explanation and solution if you are having trouble.

Here is a hint:

See the equations that have isolated x, y, z?

Add them up.

Now, notice the other equations, how can you susbtitute in and evualate?

Its pretty simple, you just have to see it!

Holy cow rom that is smart

I always thought that your profile pic was a cow until I looked closely and it was a horse, er, or maybe a pony.

Reflect the x intercept over the line of symmetry in the quadratic.

The vertex is (3,7), so the line of symmetry must be x = 3

We reflect that, so 3-(-2) = 5

3 + 5 = 8

So the x coordinate of the other x intercept is (8, 0)

Put it into standard form,

you do this by completing the square for the y terms.

Then you isolate the constant, then square root it to find the radius.

2 y-intercepts

You use combination to find cases

And the ruel for probability is the number of selected cases OVER all possible cases.