For the graph of a certain quadratic y = ax^2 + bx + c, the vertex of the parabola is (3,7) and one of the x-intercepts is (-2,0). What is the x-coordinate of the other x-intercept?

Corbella.15 Oct 10, 2019

#1**+3 **

Parabolas are symmetric.....the other zero will be the sam distance from the vertex as the one given...

from -2 to 3 is five units.....the other zero should be at 8,0

ElectricPavlov Oct 10, 2019

#2**+2 **

Reflect the x intercept over the line of symmetry in the quadratic.

The vertex is (3,7), so the line of symmetry must be x = 3

We reflect that, so 3-(-2) = 5

3 + 5 = 8

So the x coordinate of the other x intercept is (8, 0)

CalculatorUser Oct 10, 2019