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For the graph of a certain quadratic y = ax^2 + bx + c, the vertex of the parabola is (3,7) and one of the x-intercepts is (-2,0). What is the x-coordinate of the other x-intercept?

 Oct 10, 2019
 #1
avatar+26006 
0

Parabolas are symmetric.....the other zero will be the sam distance from the vertex as the one given...

 

from -2 to 3 is five units.....the other zero should be at   8,0

 Oct 10, 2019
 #2
avatar+2856 
+2

Reflect the x intercept over the line of symmetry in the quadratic.

 

The vertex is (3,7), so the line of symmetry must be x = 3

 

We reflect that, so 3-(-2) = 5

 

3 + 5 = 8

 

 

So the x coordinate of the other x intercept is (8, 0)

 Oct 10, 2019

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