CoolStuffYT

Question: Simplify \(\frac{2011!+2012!}{2011!+2010!}\).

We can factor stuff out from the numerator and denominator.

Let's factor out 2010 from both the numerator and denominator.

The numerator will become \(2010(2011+2011\times 2012)\).

The denominator will become \(2010(2011+1)\).

In fraction form, this looks like \(\frac{2010(2011+2011\times 2012)}{2010(2011+1)}\)

From there, cancel out 2010, and solve.

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I'll try to help

\(20(1-\sin^2x)+\sin4x=13\)

\(20-20\sin^2x+\sin4x=13\)

Bring all the sines to one side and numbers to the other.

\(20\sin^2x-\sin4x=7\)

Hopefully, from there you can find it.

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The x-coordinate distance is 2-(-6)=8.

Use the Pythagorean theorem (\(a^2+b^2=c^2\)).

We know that \(a\) or \(b\) equals 8 (it doesn't matter which one.

c must equal 10 because that's how long the whole thing is.

To find y, you must plug values into the theorem and get the distance.

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I friended you! I'm PureSwag.

The ^2 means that you multiply the number twice.

In other words, 5 x 5

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