CoolStuffYT

Question: Simplify $\frac{2011!+2012!}{2011!+2010!}$.

We can factor stuff out from the numerator and denominator.

Let's factor out 2010 from both the numerator and denominator.

The numerator will become $2010(2011+2011\times 2012)$.

The denominator will become $2010(2011+1)$.

In fraction form, this looks like $\frac{2010(2011+2011\times 2012)}{2010(2011+1)}$

From there, cancel out 2010, and solve.

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I'll try to help

$20(1-\sin^2x)+\sin4x=13$

$20-20\sin^2x+\sin4x=13$

Bring all the sines to one side and numbers to the other.

$20\sin^2x-\sin4x=7$

Hopefully, from there you can find it.

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The x-coordinate distance is 2-(-6)=8.

Use the Pythagorean theorem ($a^2+b^2=c^2$).

We know that $a$ or $b$ equals 8 (it doesn't matter which one.

c must equal 10 because that's how long the whole thing is.

To find y, you must plug values into the theorem and get the distance.

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I friended you! I'm PureSwag.

The ^2 means that you multiply the number twice.

In other words, 5 x 5

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