A line segment begins at (2, 5). It is 10 units long and ends at the point (-6, y) where y > 0. What is the value of y.
Use Pythagoras to find the square of the length of the line between the two points as:
(y - 5)2 + (-6 - 2)2
Set this equal to 102 and solve for y.
The x-coordinate distance is 2-(-6)=8.
Use the Pythagorean theorem (\(a^2+b^2=c^2\)).
We know that \(a\) or \(b\) equals 8 (it doesn't matter which one.
c must equal 10 because that's how long the whole thing is.
To find y, you must plug values into the theorem and get the distance.
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