A line segment begins at (2, 5). It is 10 units long and ends at the point (-6, y) where y > 0. What is the value of y.

Guest Nov 24, 2019

#1**+2 **

Use Pythagoras to find the square of the length of the line between the two points as:

(y - 5)^{2} + (-6 - 2)^{2}

Set this equal to 10^{2} and solve for y.

Alan Nov 24, 2019

#2**0 **

The x-coordinate distance is 2-(-6)=8.

Use the Pythagorean theorem (\(a^2+b^2=c^2\)).

We know that \(a\) or \(b\) equals 8 (it doesn't matter which one.

c must equal 10 because that's how long the whole thing is.

To find y, you must plug values into the theorem and get the distance.

You are very welcome!

:P

CoolStuffYT Nov 24, 2019