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A line segment begins at (2, 5). It is 10 units long and ends at the point (-6, y) where y > 0. What is the value of y.

 Nov 24, 2019
 #1
avatar+29243 
+3

Use Pythagoras to find the square of the length of the line between the two points as:

 

(y - 5)2 + (-6 - 2)2

 

Set this equal to 102 and solve for y.

 Nov 24, 2019
 #2
avatar+1068 
-1

The x-coordinate distance is 2-(-6)=8.

Use the Pythagorean theorem (\(a^2+b^2=c^2\)).

We know that \(a\) or \(b\) equals 8 (it doesn't matter which one.

c must equal 10 because that's how long the whole thing is.

To find y, you must plug values into the theorem and get the distance.

 

You are very welcome!

:P

 Nov 24, 2019

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