CPhill

Correct, hectictar.....no angle can be < 61°

5i √ [ -54 ]  =

5i √-1  *√ 9 * √ 6  =

5i (i) * 3  * √ 6  =

5 i^2  *  3 * √ 6  =

5 * (-1)  * 3  * √6  =

-15 √6

i^39  =

(i^2)^18 *  (i^2) * i^1  =

(-1)^18 *  (-1)  * i  =

1  *  -1   *   i   =

- i

0.4i  -  i   =

0.4i  - 1i  =

-0.6i

-2i  * -3i  =

6i^2  =

6 (-1)  = 

-6

Thanks, GA!!!!!

Let's order the data

1,1,2,5,6,7,10,10,13, 18, 19, 20, 24, 26, 27, 31, 36, 54, 63, 67

The average age  is  22 yrs

The sum  of the ages  is  440 yrs

When  two  of the turtles leave, the average is  21 yrs....and there are 18 turtles left

So....the sum of the ages is  21 * 18  = 378

And the difference  in the sums  is  62

The only two values that sum to 62  are  26 and 36

So.....the box turtle must have been 36 and the map turtle must have been 26

Mmmm... let's see...

First....let's order the data by days missed 

0,0,0,1,2,2,2,2,3,4,5,5,5,5,5

The median number of days missed  is the middle value, 2  days

The mean (average)  days missed  is :

[ 3(0) + 1  + 4(2) + 3 + 4 + 5(5) ]  /  15  = 

41 / 15   days

So   the mean number of days exceeds the median number of days by   

41/15  -  2

41/15  -  30/15  =

11/15  days

Thanks, X².....but......your answer might have been more illustrative...

Considering the "rainbow" colors, the  percent who preferred red  can be found thusly :

Red  = .13 * 500  =  65

Orange  = .04 * 500  = 20

Yellow = .05 * 500  =  25

Green   =  .15 * 500  = 75

Blue  =  .16 * 500  =  80

Purple  = .12 * 500  =  60 

So..... the %  that preferred red is

65  /  [  65 + 20 + 25 + 75 + 80 + 60 ]  =

65  /  325    =

1 / 5   =

20%

ax^2 + bx  + a

The product of the roots  =  a/a  =  1

So....let r be the other root

So

4r  =  1   ⇒  r  = 1/4