For the data whose frequency histogram is shown, by how many days is the mean number of days missed per student greater than the median number of days missed per student for the 15 students? Express your answer as a common fraction.

SmartMathMan Dec 20, 2017

#1**+2 **

Mmmm... let's see...

First....let's order the data by days missed

0,0,0,1,2,2,2,2,3,4,5,5,5,5,5

The median number of days missed is the middle value, 2 days

The mean (average) days missed is :

[ 3(0) + 1 + 4(2) + 3 + 4 + 5(5) ] / 15 =

41 / 15 days

So the mean number of days exceeds the median number of days by

41/15 - 2

41/15 - 30/15 =

11/15 days

CPhill Dec 20, 2017