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For the data whose frequency histogram is shown, by how many days is the mean number of days missed per student greater than the median number of days missed per student for the 15 students? Express your answer as a common fraction.

 

 Dec 20, 2017
edited by SmartMathMan  Dec 20, 2017
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Mmmm... let's see...

 

First....let's order the data by days missed 

 

0,0,0,1,2,2,2,2,3,4,5,5,5,5,5

 

The median number of days missed  is the middle value, 2  days

 

The mean (average)  days missed  is :

 

[ 3(0) + 1  + 4(2) + 3 + 4 + 5(5) ]  /  15  = 

 

41 / 15   days

 

So   the mean number of days exceeds the median number of days by   

 

41/15  -  2

 

41/15  -  30/15  =

 

11/15  days

 

 

cool cool cool

 Dec 20, 2017

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