Note, DS, that we have the law of exponents that says an / am = a n-m
So.....look at the fraction....we have
7 * ( a2 / a5) and using this law, we have
7 * (a 2-5 ) = 7 * a-3
And remember that a-n = 1 / an
So.......
7 * a-3 = 7 * ( 1 / a3) = (7 / a3 )
So...our answer should be
a2b - (7/a3)
Does that help ???
