n*√n / 4√n^2

n*√n / 4√n^2

4√n^2 would be the same as √n (i think)

so we have: n*√n / √n

wich would give us n.

This is just a guess. I might be wrong

n*√n / ⁴√n^2     so we have, using some exponent laws......

n^3/2 / (n² )^1/4 =  

n^{(3/2 )} / n^(1/2) =

(n^{3/2 - 1/2} )   = n¹   =  n       ........  (with the restriction that n ≠ 0)