CPhill

1.2*10⁵ = 120,000

1.2 *10⁶ = 1,200,000

So the second is closer to one million...

1.1275 x 10²

1.5 x 10¹

OK...we have

x + y =41    and

x - y = 17   adding the two equations, we have

2x = 58   divide by two on both sides

x = 29

And, using the first equation to find y, we have

29 +  y = 41     subtract 29 from both sides

y = 12

And that's it......x = 29 and y = 12   !!!!

Am apple is am fruit that grows on am tree. It am usually picked about this time in the US.

Am apple is also am computer. Just remember that one am edible and the other am not!!!

That's wot I know about this........

The x component is given by (290N)cos(33°) = about 243.2N

We need to solve the inequality

x² + x -20 > 0

In these cases, I usualy like to just set this up as an equality and find some "test" points !!!

So we have

x² + x -20 = 0    and factoring, we have

(x + 5) (x -4) = 0      and setting each factor to  0, we have that x = - 5  and x = 4

This tells us that the possible solutions come from these intervals (-∞, -5), (-5, 4) or (4,∞)...usually, in these quadratic inequalities, if the middle interval "works," the two "outside" intervals don't - or vice-versa !!!

Let's pick a point in the interval (-5, 4) and see if it "works" in the original problem - I always like "0"

So we have

(0)² + (0) - 20 > 0     and that clearly isn't true

So...my 'guess' is that the solutions come from the intervals (-∞, -5) and (4,∞)

Here's the graph of y = x² + x - 20

If we have

y = 4cosx -1

This is the normal cosine graph with an amplitude of 4 that is shifted "down" one unit. Thus, the normal cosine graph is shifted "down' by one unit and "stretched" vertically.

We need to solve the inequality

-6x - 12 > 0   add 12 to both sides

-6x > 12     divide both sides by -6 and reverse the direction of the inequality sign

x < -2

Well, if we have a 110 gram alloy that contains 16%  copper, then there must be .16 * 110 = 17.6 g of copper in the alloy

And if we have a 210 gram alloy that contains 64% copper, then there must be .64 * 210 = 134.4 g of copper in this alloy

So , the final mixture contains   (17.6 + 134.4)g of copper = 152g of copper

And the total final mixture of both alloys = (110 + 210) g  = 330g

And if 152g of this is copper...... then, 152 / 330 = about 46% is copper