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An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 110 grams of an alloy containing 16% copper with 210 grams of an alloy containing 64% copper. How many grams of copper are in the resulting mixture? and what percentage of the resulting mixture is copper?

 Sep 25, 2014

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 #1
avatar+129840 
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Well, if we have a 110 gram alloy that contains 16%  copper, then there must be .16 * 110 = 17.6 g of copper in the alloy

And if we have a 210 gram alloy that contains 64% copper, then there must be .64 * 210 = 134.4 g of copper in this alloy

So , the final mixture contains   (17.6 + 134.4)g of copper = 152g of copper

And the total final mixture of both alloys = (110 + 210) g  = 330g

And if 152g of this is copper...... then, 152 / 330 = about 46% is copper

 

  

 Sep 25, 2014
 #1
avatar+129840 
+5
Best Answer

Well, if we have a 110 gram alloy that contains 16%  copper, then there must be .16 * 110 = 17.6 g of copper in the alloy

And if we have a 210 gram alloy that contains 64% copper, then there must be .64 * 210 = 134.4 g of copper in this alloy

So , the final mixture contains   (17.6 + 134.4)g of copper = 152g of copper

And the total final mixture of both alloys = (110 + 210) g  = 330g

And if 152g of this is copper...... then, 152 / 330 = about 46% is copper

 

  

CPhill Sep 25, 2014

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