CPhill

254 x 12 = 3048

Good job by Melody and heureka....points for both........maybe some of my detective work is rubbing off on Melody ..... LOL!!!

We can model this with the following inequality

50x + 160 ≤ 1000      where x is the number of boxes....so, subtracting 160 from each side, we have

50x ≤ 840                  divide both sides by 50

x ≤ 16.8 boxes     ....but since he can't bring up partial boxes, round down to 16

Geno's method will work....but here's something that might be easier........ using...... y^2 = 2x

Divide both sides by 2...so we have

y^2/2  = x

Now, nstead of selecting "x" values, just select a few y values.....I suggest 0, 2, 4, 6 and -2,-4, -6 ....and find the associated "x" for each one......we don't have to take any square roots that way...

If you do this correctly...you should end up with  parabola facing to the "right" with its vertex  at the origin !!!

C=5/9(F - 32)   and substituting 62 for "F" we have

C = 5/9(62 - 32)

C = 5/9(30)

C= 150/9

C = about 16.7° C

If we know the length of the diagonals, the area is just (1/2)d₁d₂   where d₁ and d₂   are the diagonal lengths.

Hey, ryan.....why don't you join the site???......we have lot's of people who can help you and you may be able to help us, too.......

Geno is correct.......

Here are the names of the parts.......

Mantissa × 10^{Characteristic}

Go with geno's answer...it's better than mine !!! (We actually could have 26 students !!!)