CPhill

And I assume you'd like to know its total goal??? If so...

Note that 2/5ths represents only 2 "parts" of their goal. So 2370/2 = $1185. So, each part is $1185. And 5 parts is the total goal, so......5 x $1185 = $5925

2cos(x)(2cos(x-1)^2)+1=2sin(x)^2

Not anymore, it's not.........now.....MINE is more fun !!!!!!

Using

N = 2000e^kt       where N is the number of bacteria at any time, t ≥ 0........

We need to solve for the constant k........and we're told that......  

4000 =2000e^k(.75)    divide both sides by 2000

2 = e^.75k                  take the natural log of both sides

ln2 =lne^.75k             and by a log property, we can write

ln2 =.75k (lne)           and lne = 1   ......so....

ln2 =.75k                 divide both sides by .75

k = ln2/.75

So, our function  is

N =2000e^(ln2/.75)t

And to find out when N = 32000, we have

32000= 2000e^(ln2/.75)t        divide both sides by 2000

16 = e^(ln2/.75)t                    take the ln of both sides

ln 16 = lne^(ln2/.75)t              and we can write

ln 16 = (ln 2/.75)t             divide both sides by ln2/.75

[ln16]/ [ln2/.75] = t =  3 hrs.

Triangle LMN has vertexes at L(-1, -6), M(1, -6), and N(1, 1). Find the measure of angle N to the nearest degree.

Let's translate N so that it lies at (0,0)...then L= (-2, -7) and M = (0, -7).....this will make the calculation of the distances easier.......

So NL = √(4 + 49) = √(53)

And NM = √49 = 7

And ML = √4 = 2

And LMN forms a right triangle, with angle NML = 90

So.....using the Law of Sines, we have

NL / sin 90 = ML / sin(LNM)

√(53) = 2/sin(LNM)

sin(LNM) = 2/√(53)

sin-1[2/√(53] = LNM ≈15.945° ≈ 16°

a^2+ab = 15    →  b = (15- a^2)/a

2b^2 = 20 - 2ab  →   b^2 = 10 - ab   →  [(15 - a^2)/a]^2 = 10 - (15 - a^2)   →

(15 - a^2)^2 = a^2(a^2 - 5)   →

225 - 30a^2 + a^4 = a^4 - 5a^2    →

-25a^2 + 225 = 0

25a^2 - 225 = 0

a^2 - 9 = 0

(a + 3) (a - 3) = 0

a = -3  a = 3

b = -2  b = 2

Then....... -3 + -2 = -5

Play nice, Melody.....!!!!!

A tangent is a guy who has gotten too much sun at the beach.......

10-11d>-5d-4    add 5d to both sides

10 - 11d + 5d > -4        subtract 10 from both sides

-11d + 5d > -14           simplify

-6d > -14                    divide both sides by -6 and reverse the inequality sign

d < -14/-6

d < 7/3

-5 [5-(-9)] = -5[5 + 9] = -5[14] = -70   ......remember....a negative outside parentheses or brackets just changes the signs on the terms inside