If we choose the one who is fine either way to be a spiker....we have to choose one of 6 spikers and one of 4 setters = 6 * 4 = 24 ways
If we choose the one who is fine either way to be a setter we have to choose one of 5 spikers and one of 5 setters = 5 * 5 = 25 ways
So 25 + 24 = 49 ways
r = 6 sin θ
In the boxes
f(x) =6sin x
r
Not sure about this one
circle with a radius of 3
Sorry.....just a typo !!!.....corrected !!!
I could do this algebraically, but a graph seem quicker
The bisected angle PRQ sets up the following relationship
x + 2 /12 = 12 / 8
x + 2 / 12 = 3 / 2 multily both sides by 12
x + 2 = 12 ( 3/2)
x + 2 = 18
x = 16
Using the intersecting chord theorem
RA * SA = PA * QA
7 * 7 = PA * 9
49 = PA * 9
49/9 = PA
PA + QA = 49/9 + 9 = [ 49 + 81] / 9 = 130 / 9 = the diameter
So......the radius = 1/2 of this = 130 /18 = 65 / 9
We can only get a 0 or a positive from a positive square root
And note that sqrt (x^2) is defined as absolute value (x)
So....the range is [ 0 , infinity )
Interior angle of a regular pentagon = 108
Interior angle of a regular hexagon = 120
108 / 120 = ( 9 * 12) / (10 * 12) = 9 /10
f(-2) = (-2)^2 - 2 = 2
f(2) = 2(2) - 20 = -16
So
2 - 16 + f(a) = 0
-14 + f(a) = 0
f(a) = 14
In the first function f(a) = 14 so a^2 - 2 = 14 ⇒ a^2 = 16 ⇒ a = -4 (a must be < 0)
In the second function f(a) = 14 so 2a -20 = 14 ⇒ 2a = 34 ⇒ a = 17
The positive difference is 17 - - 4 = 21
Dang, AnswerMachine beat me to it !!!!