(20 - 2 ] * 2 = 36
[ 22 * 2 ] - 0! = 43
[ 2 (20) ] - 2 = 38
[ .2^--2 + 0! ] * 2 = 52
[.2^-2 - 0! ] * 2 = 48
(20/2)^2 = 100
Here's a few ....maybe I can think of some others
[.2^-2 ] *2 - 0! = 49
[.2^-2] * 2 + 0! = 51
[.2^-2] * 2 / 0! = 50
C (20, 2) / 2 = 95
(2 + 2)! * ( 2! + 0!) = 72
(2 + 2)! + 20 = 44
(.2^-2) + 20 = 45
[ 2^(2! + 0!) ] ^2 = 64
20 + 22 = 42
1. Divide the circumference by 2pi
2. This gives the radius
3. Plug the radius into pi * (radius)^2 and Voila !!!.....that's the area
Can we combine digits ???....such as 2, 0 = 20 ????
3/5 = B / 35 cross-multiply
35 * 3 = 5 B
105 = 5 * B
105 / 5 = B = 21 slices of bread
Solve for the radius
4.71 = 2 (3.14) * r
r = 4.71 / ( 2 * 3.14) = .75 ft
Plastic needed = (3.14) (.75)^2 = 1.8 sq ft
P - .44P = 39
.56 P = 39
P = 39 / .56 = $69.64 = original price
The original price has to be greater than the on-sale price
z^49 + z^50 + z^51 + z^52 =
z^49 + z^51 + z^50 + z^52
z^49 ( 1 + z^2) + z^50 ( 1 +z^2)
z^49 ( z^2 + 1) + z^50 ( z^2 + 1) =
z^49 (0) + z^50 (0) =
0
Take the sine inverse to find x
arcsin (-7/10) = x ≈ -44.43°
If we need x to be positive then 180 + 44.43 = 224.43°
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