For a real number x, find the number of different possible values of \(\lfloor{x}\rfloor + \lfloor{-x}\rfloor\).
idk rly.
Look at cases
If x is an integer : floor (x) = x and floor (-x) = -x
So x + -x = 0
If x is not an integer : floor (x) = x and floor (-x) = -x - 1
So x + - x -1 = -1
So
We have two possible values 0 and -1
thx phil
Welcome !!!!
+505 
