Here's one more final take on this problem for me.....note that no number is divisible by 7 or 11.
This means that, at least one 7 and one 11 must be used to form any possible number. Thus, 18 will be used in the addition process.
So......
61 - 18 = 43 and neither 7 or 11 divides this......43 - 18 = 25 and neither 7 or 11 divides this....25 - 18 = 7 and 7 divides itself
So.....61 = 3(18) + 7 = 3(7 + 11) + 7 = 4(7) + 3(11)
60 - 18 = 42 and note that 7 divides this....so 60 = 1(18) + 6(7) = 1(11 + 7) + 6(7) = 7(7) + 1(11)
58 - 18 = 40 ......40 - 18 = 22......22 - 18 = 4 .....note, however.....58 - 11 = 47 .......47 - 11 = 36 and 18 divides this
So...58 = 2(11) + 2 (18) = 2(11) + 2(11 + 7) = 4(11) + 2(7)
And we have seen that 59 cannot be made by any linear combo of 7 and 11
