Dimitristhym

Thank you very much guys for help!

Thank you! Rom

Delete someone mode my comment thank you.

Exactly! You have something to add in my answer or there are something whitch don't tike you?

Thank you.

I will use distributive property:

$(2\sqrt{3x}-2)(3\sqrt{3x}+5)<=>2\times 3(\sqrt{3x})(\sqrt{3x})+5\times2(\sqrt{3x})-2\times3(\sqrt{3x})-2\times5<=>6\times3x+10(\sqrt{3x})-6(\sqrt{3x})-10<=>18x+4(\sqrt{3x})-10$

Finally $18x+4(\sqrt{3x})-10$

$0≤θ≤2π$ (1)

$3sinθ=sinθ -\sqrt{3}<=> 3sinθ-sinθ= -\sqrt{3}<=> 2sinθ= -\sqrt{3} <=>sinθ= -\frac{\sqrt{3}}{2}<=>sinθ=-sin(\frac{π}{3}),sinθ=-sin(\frac{2π}{3})<=>sinθ=sin(-\frac{π}{3}),sinθ=sin(-\frac{2π}{3})$

With (1) $sinθ=sin(2π-\frac{π}{3}),sinθ=sin(2π-\frac{2π}{3})<=>sinθ=sin(\frac{5π}{3}),sinθ=sin(\frac{4π}{3}) <=>θ=\frac{5π}{3},θ=\frac{4π}{3}$

So $θ=\frac{5π}{3},θ=\frac{4π}{3}$

You are right but we try with 6 answers to help him.I solve it because mabe understand the consept of the exercise for this reason I write tit like this Area = area1 + area2 and if understand the consepm will understand and the operations.

I was student and I have students I know how it is.

Have a nice day/night.

I solve it step by step we told him its (side)^2 side=5 and he told 5^2 = 12.5...

Be more polite and also I talk with him in p.m.

After all instead my answer and all this answers of CPhill what will suggested you as an answer?

There are a theorem witch say:

An exterior angle of a triangle is equal to the sum of the other two angles of the triangle.

So the measure of the smallest exterior angle of the triangle equals to the sum of the other two angles of the triangle.

Aha ok thank you I was wandering if it was a mathematical symbol witch I didn't know.