I have this matrix A= \(\begin{bmatrix} 1 && -1 && 0 && 1 \\ 3 && 1 && -1 && 2 \\ 7 && 1 && -2 && 8 \end{bmatrix}\) and i need to find matrix P,Q so that PAQ= \(\begin{bmatrix} Irxr&& 0 \\ 0 && 0 \end{bmatrix}\) But i find after trades for lines the 3,4 element its 1 and this cannot change with trades at columns.I'm correct and if not where im wrong? Thank you!

Dimitristhym Nov 1, 2018

#1

#3**+1 **

So you're saying that PAQ is an identity matrix with an unknown number of columns?

Guest Nov 1, 2018

#4**+1 **

No identity matrix will included in PAQ and all other will have 0 exp. Will be 3 lines and 4 and will have identity matrix 1x1 or 2x2 or 3x3 and all other its 0

Dimitristhym
Nov 1, 2018