One interior angle of a triangle has a measure that is equal to the sum of the measures of the other two angles of the triangle. What is the measure of the smallest exterior angle of the triangle in degrees?
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Let a and b be the measures of the two other angles of the triangle.
the sum of the interior angles in a triangle = 180°
a + b + (a + b) = 180°
2(a + b) = 180°
a + b = 90°
the measure of the smallest exterior angle = 180° - the measure of the largest interior angle
the measure of the smallest exterior angle = 180° - ( a + b )
the measure of the smallest exterior angle = 180° - 90°
the measure of the smallest exterior angle = 90°
There are a theorem witch say:
An exterior angle of a triangle is equal to the sum of the other two angles of the triangle.
So the measure of the smallest exterior angle of the triangle equals to the sum of the other two angles of the triangle.
Let a and b be the measures of the two other angles of the triangle.
the sum of the interior angles in a triangle = 180°
a + b + (a + b) = 180°
2(a + b) = 180°
a + b = 90°
the measure of the smallest exterior angle = 180° - the measure of the largest interior angle
the measure of the smallest exterior angle = 180° - ( a + b )
the measure of the smallest exterior angle = 180° - 90°
the measure of the smallest exterior angle = 90°