Hi I need your help:
Find the solution: τ=(1,2,5,7)(3,4,6,7)(1,4,8,9,3)(4,7,2)
The answer is (1,7)(2,8,9,4,3,6)(5)=>(2,8,9,4,3,6)(1,7)
An other ex. is this:σ=(1,3,5)(2,7)(11,1,4)(5,6,2,8,9)(7,3)(4,5,2,1)
The answer is (1,11,3,2,4,6,7,5,8,9)(10)=>(1,11,3,2,4,6,7,5,8,9)
I don't know/understand the steps to find this answer.
Thank you!
2.)
An other ex. is this: σ=(1,3,5)(2,7)(11,1,4)(5,6,2,8,9)(7,3)(4,5,2,1)
The answer is (1,11,3,2,4,6,7,5,8,9)(10)⇒(1,11,3,2,4,6,7,5,8,9)
Start with x=1 in k(x)
f∘g∘h∘i∘j∘kxk(x)j(k(x))i(j(k(x)))h(i(j(k(x))))g(h(i(j(k(x)))))f(g(h(i(j(k(x))))))(1,3,5)∘(2,7)∘(11,1,4)∘(5,6,2,8,9)∘(7,3)∘(4,5,2,1)1444111111111111111133377722211144445566666662277773333552288888889999999555110101010101010
Permutation cycles:
(1, 11, 3, 2, 4, 6, 7, 5, 8, 9) (10)