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avatar+343 

Hi I need your help:

Find the solution:  τ=(1,2,5,7)(3,4,6,7)(1,4,8,9,3)(4,7,2)

The answer is (1,7)(2,8,9,4,3,6)(5)=>(2,8,9,4,3,6)(1,7)

 

An other ex. is this:σ=(1,3,5)(2,7)(11,1,4)(5,6,2,8,9)(7,3)(4,5,2,1)

The answer is (1,11,3,2,4,6,7,5,8,9)(10)=>(1,11,3,2,4,6,7,5,8,9)

I don't know/understand the steps to find this answer.

Thank you!

 Jun 2, 2019
 #1
avatar+26396 
+2

2.)

An other ex. is this: σ=(1,3,5)(2,7)(11,1,4)(5,6,2,8,9)(7,3)(4,5,2,1)
The answer is (1,11,3,2,4,6,7,5,8,9)(10)(1,11,3,2,4,6,7,5,8,9)

 

Start with x=1 in k(x)

 

fghijkxk(x)j(k(x))i(j(k(x)))h(i(j(k(x))))g(h(i(j(k(x)))))f(g(h(i(j(k(x))))))(1,3,5)(2,7)(11,1,4)(5,6,2,8,9)(7,3)(4,5,2,1)1444111111111111111133377722211144445566666662277773333552288888889999999555110101010101010

 

Permutation cycles:
(1, 11, 3, 2, 4, 6, 7, 5, 8, 9) (10)

 

laugh

 Jun 3, 2019
 #2
avatar+343 
+1

Oh I understand it! 

Thank you very much.The first τ it's wrong.

 Jun 5, 2019

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