In right triangle ABC with the right angle at vertex A, altitude AE is drawn from vertex A to hypotenuse BC, AE = 21, and CE = 20. Find the length of BC. Round your answer to the nearest hundredth.
Triangles ABC, ACE and ABE are similar.
AE = 21
CE = 20
Angle ACB = ? tan(ACB) = AE / CE ∠ ACB = 46.397°
BE = tan(BAE) * AE BE = 22.05
BC = CE + BE BC = 42.05