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The length of a rectangle is 3 more than its width. The perimeter of the rectangle is 58 cm. What are the rectangle’s dimensions?

 Feb 10, 2020
 #1
avatar+109740 
+1

Let the width   = W

 

Let the length =  W + 3

 

The perimeter  =  2 ( W + L)

 

So

 

58 =  2 ( W  + (W + 3) )      divide both sides by  2

 

29  = 2W + 3         subtract  3  from both sides

 

26  = 2W     divide both sides  by  2

 

13 = W  = the width

 

And the length  = W + 3   = 16

 

 

cool cool cool

 Feb 10, 2020
 #2
avatar+531 
+2

The length of a rectangle is 3 more than its width. The perimeter of the rectangle is 58 cm. What are the rectangle’s dimensions?

 

( 58 - 2*3) / 4 = 13            Rectanle sides are:  a = 13cm   b = 16cm  indecision

 Feb 10, 2020

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