Dragan

Rectangle area is 40 u²

^{Area MBCN = 3/8 * 40}

In trapezoid ABCD, sides AB and CD are parallel, angle A = angle D, and angle C = 3 times angle B. Find angle B.

Trapezoid ABCD is the right trapezoid because its two angles are the right angles.

∠A = ∠D = 90°

∠B : ∠C =  1 : 3

∠B = 1/4 * 180° = 45°

∠C = 3/4 * 180° = 135°   

Angle  BAD = 180° - ( 15° + 50° +90° ) 

x = [sin(60°) * 8] / sin(45°) = 9.797958971 units  

13pi/18 * 180/pi = 13 * 180 / 18 = 130°        

Arc  L = 18.4 in

r = { [ (360° * 18.4) /130° ] / pi} / 2 

This works also ( at least mathematically)  

2x - 6 = 6

2x = 12

x = 6

2 * x - 6 = 6                                                                                                     :        

Let IJKLMN be a hexagon with side lengths IJ = LM = 2, JK = MN = 3, and KL = NI = 8. Also, all the interior angles of the hexagon are equal. Find the area of hexagon IJKLMN.

The area of hexagon is:   A = 39.83716857 u²   

9 and 41 what is a third number to form a right triangle

1)     sqrt ( 9² + 41² ) = 41.97618372     ( This is the number too ) 

2)     sqrt ( 41² - 9² ) = 40       

1) A, B, C, and D are points on a circle, and segments AC and BD intersect at P, such that AP = 8, PC = 1, and BD = 6. Find BP, given that BP < DP.

Let AC be a side of an inscribed square. Let O be a center of a circle, and N is the intersection point of BD and CO.

AP = 8       PC = 1        BD = 6        ∠(CPN) = 45°

PN = sqrt [(PC)² /2]  =  sqrt(1/2) = [ sqrt(50)] /10  =  sin(45°) = cos(45°) = 0.707106781

BP = ( BD/2 ) - PN = 2.292893219 units