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9 and 41 what is a third number to form a right triangle

 Mar 23, 2020

Best Answer 

 #1
avatar+1956 
+3

Since a^2+b^2=c^2 or c^2-b^2-a^2

 

Let's say that a=9

                      c=41.

 

41^2-9^2= 1600

 

Now, square root 1600, which will get you 40.

 

Therefore, 40 is a side length that will form a right triangle.

 

Hope this helped!

 Mar 23, 2020
 #1
avatar+1956 
+3
Best Answer

Since a^2+b^2=c^2 or c^2-b^2-a^2

 

Let's say that a=9

                      c=41.

 

41^2-9^2= 1600

 

Now, square root 1600, which will get you 40.

 

Therefore, 40 is a side length that will form a right triangle.

 

Hope this helped!

CalTheGreat Mar 23, 2020
 #2
avatar+111321 
+1

Correct-A-Mundo, CTG   !!!!!

 

A "Best Answer "....

 

cool cool cool

CPhill  Mar 23, 2020
 #3
avatar+1956 
+1

LOL! Thanks!!!

CalTheGreat  Mar 23, 2020
 #4
avatar+694 
+1

9 and 41 what is a third number to form a right triangle

 

1)     sqrt ( 9² + 41² ) = 41.97618372     ( This is the number too ) laugh

 

2)     sqrt ( 41² - 9² ) = 40       indecision

 Mar 23, 2020
edited by Guest  Mar 23, 2020
 #5
avatar+23566 
+1

BBBBUUUUUTTTT   there is ANOTHER possibility

 

if  9  and 41 are the LEGS of the triangle

 

9^2 + 41^2 = hyp^2      Hypotenuse = 41.976    is the third side  

                      (the 40 third side answer is likey the correct one,,,,but you should realize that this solution is a correct answer TOO )

 Mar 23, 2020
 #6
avatar+1956 
0

That's true! The square root of 1760.

CalTheGreat  Mar 24, 2020
edited by CalTheGreat  Mar 24, 2020
 #7
avatar+483 
+1

No it would be the square root of 1762,

 

\(\sqrt{9^2 + 41^2} = \sqrt{81 +1681} = \sqrt{1762}\)

jfan17  Mar 24, 2020

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