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# Pythagorean Therom

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80
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9 and 41 what is a third number to form a right triangle

Mar 23, 2020

#1
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Since a^2+b^2=c^2 or c^2-b^2-a^2

Let's say that a=9

c=41.

41^2-9^2= 1600

Now, square root 1600, which will get you 40.

Therefore, 40 is a side length that will form a right triangle.

Hope this helped!

Mar 23, 2020

#1
+3

Since a^2+b^2=c^2 or c^2-b^2-a^2

Let's say that a=9

c=41.

41^2-9^2= 1600

Now, square root 1600, which will get you 40.

Therefore, 40 is a side length that will form a right triangle.

Hope this helped!

CalTheGreat Mar 23, 2020
#2
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Correct-A-Mundo, CTG   !!!!!   CPhill  Mar 23, 2020
#3
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LOL! Thanks!!!

CalTheGreat  Mar 23, 2020
#4
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9 and 41 what is a third number to form a right triangle

1)     sqrt ( 9² + 41² ) = 41.97618372     ( This is the number too ) 2)     sqrt ( 41² - 9² ) = 40 Mar 23, 2020
edited by Guest  Mar 23, 2020
#5
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BBBBUUUUUTTTT   there is ANOTHER possibility

if  9  and 41 are the LEGS of the triangle

9^2 + 41^2 = hyp^2      Hypotenuse = 41.976    is the third side

(the 40 third side answer is likey the correct one,,,,but you should realize that this solution is a correct answer TOO )

Mar 23, 2020
#6
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That's true! The square root of 1760.

CalTheGreat  Mar 24, 2020
edited by CalTheGreat  Mar 24, 2020
#7
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No it would be the square root of 1762,

$$\sqrt{9^2 + 41^2} = \sqrt{81 +1681} = \sqrt{1762}$$

jfan17  Mar 24, 2020