Let angle BAC be an X
10X -12 + 2X = 180
X = 16
Angle DAC = 2X
Nope, there's only one hypotenuse for this right triangle, and its length is 13.
Altitude L = (5 * 12 )/13
O is the center of a circle
M is a midpoint of a diagonal BD
tan(BDC) = 3/4 angle BDC = 36.86989765º
Angles BDC, BNM, and CNO are congruent
BN = MB / sin(BNM) = 4.166666666
CN = BN - BC = 1.1666666666
OC = sin(CNO) * CN = 0.7 or 7/10
The ratio of peach area to the area of octagon is 1 : 2
It is correct!!!
"The probability that I choose an I is 1/9, and the probability that I pick another I right after is 1/8"
Let me get this straight: on the 1st draw, the probability (1/9) is lesser than on the second one (1/8) ?!?!
"x" is opposite the right angle
Both triangles are 30-60-90
Let the hypotenuse of a smaller triangle be a Y
Y = 1 / cos(60°) = 2
X = 2 / sin(30°) = 4
I think I made a huge mistake. I've just realized that the dimension 4 is given at a certain angle.
corrections: V = 5 * 1.5 * sqrt(3) V = [10 * 3 * 2sqrt(3)] / 8
I apologize, Alan!!! Your answer is, of course, correct!!!
x + y = sqrt( 9^2 + 12^2 ) = 15
z = ( 9 * 12 ) / 15 = 7.2
x+y+z = 22.2
