In the diagram below, A is on line segment CE, and line segment AB bisects angle DAC. If line segment DA is parallel to line segment EF and angle AEF = angle BAC multiplied by 10 and subtracted by 12 degrees, then what is angle DAC in degrees?
+128406 If we extend FE in the direction of E to G , then angle DEG = 180 - AEF = 180 - (10*BAC - 12)
But since DA is parallel to EF this angle will equal DAC = 2 ( BAC)
Therefore....this means that
2(BAC) = 180 - (10*BAC - 12)
2(BAC) + (10*BAC - 12) = 180
12BAC -12 = 180 add 12 to both sides
12BAC = 192 divide both sides by 12
BAC = 16
Therfore, angle DAC = 2 (BAC) = 2(16) = 32°
