Great job,Heureka!It,s correct.
Does this question challenge you?
Yes.I believe it's correct.
Thanks Alan,Melody,and Dbg4thebest.
Hi,Melody.
I think there is something wrong in anwser.
In your second step,f(tan(x))=tanx*(1-tanx)/sec^2(x)
=tanx*cos^2(x)*(1-tanx)
=cosx*sinx*(1-tanx)
.......Can anyone just tell me the anwser?This question is very important to me.Thank you!
f(b)=(b-b^2)/(1+b^2),
f(tan x)=[tan(x)-tan^2(x)]/[cos^2(x)/cos^2(x)+sin^2(x)/cos^2(x)]
=[tan(x)-tan^2(x)]/[1/cos^2(x)]
=[tan(x)-tan^2(x)]*cos^2(x)
=[sin(x)/cos(x)-sin^2(x)/cos^2(x)]*cos^2(x)
=sin(x)cos(x)-sin^2(x) or =1/2*sin2x+1/2*cos2x-1/2
Yes,it is like a fraction.the ratio of men to woman is 5:3,so the ratio of women to total people is 3:8=3/8
(I pretty sure that I got the right anwse,but I dont know why the book give the anwser is D 11)
Hello friends!
I am doing a math practice book.And I got a different anwser with the book's given.Please help me.
(I realize that golden rectangle and kepler triangle are different,Thank you CPhill!)