+584 In the equation x^2+mx+n=0,m and n are intergers.The only possible for x is -3.What is the value of m?
A.3
B.-3
C.6
D.-6
E.9
+15000 Hello fiora!
In the equation x^2+mx+n=0,m and n are intergers.
The only possible for x is -3.What is the value of m?
A.3
B.-3
C.6
D.-6
E.9
\(x^2+mx+n=0\)
\(x = -3\)
\(\left(x+ 3\right) ^{2}= x^{2} + 6x+ 9= 0\)
\(m = 6 \)
\(Solution\ C\ is\ correct.\)
Greeting asinus :- ) 
!
