+0  
 
0
740
0
avatar+583 

\(T=\int_{0}^{T}dt=\int_{0}^{L}\frac{dt}{ds}ds=\int_{0}^{L}\frac{ds}{v}=\frac{1}{\sqrt{2g}}\int_{0}^{L}\frac{ds}{\sqrt{{y}_{1}-y}} =\frac{1}{\sqrt{2g}}\int_{{x}_{1}}^{{x}_{3}}\sqrt{\frac{1+{y'}^{2}}{y}}dx \)

 
off-topic
 Mar 20, 2019

2 Online Users