GYanggg

Hey supermanaccz!

If \(127 \equiv 7 \pmod{n}\), then n is a divisor of 127 - 7 = 120.

The prime factorization of 120 is \(2^3 \cdot 3 \cdot 5\)

which has \((3 + 1)(1 + 1)(1 + 1) = 16\) positive divisors.

Therefore, there are 16 possible values of n.

I hope this helps,

Gavin.

There was the same question 1 day ago, https://web2.0calc.com/questions/how-many-positive-integers-n-satisfy-127-equiv-7

Hey RB!

If \(127 \equiv 7 \pmod{n}\), then n is a divisor of 127 - 7 = 120.

The prime factorization of 120 is \(2^3 \cdot 3 \cdot 5\)

which has \((3 + 1)(1 + 1)(1 + 1) = 16\) positive divisors.

Therefore, there are 16 possible values of n.

I hope this helps,

Gavin.

When you add everything up, you reduce the fraction,

Would you like the solution?

To find the total amount of people, we use an algorithm.

59 + 37 + 54 - 25 - 12 - 28 + 10 = 95.

There are 95 people who have any type of fruit at all.

This means that we can find the amount of people without any fruit. 

100 - 95 = 5

There are 5 people with no fruit.

I hope this helped,

Gavin

The problem asks for consecutive intergers. 

10 + 11 = 21

The largest posible number of positve, consecutive intergers must start with 1, since it is the smallest positive integer.

1 + 2 + 3 + 4 + 5 + 6 = 21

This is the largest amount of consecutive integers. 

6 is your answer. 

I hope this helped,

Gavin.

Hey there!

We need to factor out as much as we can in your cube root.

After we do, we have:

-4 times the cube root of 2.

I hope this helped,

Gavin. 

Your welcome!

Did you have the same question too?

Never mind, I though the denominator was \(x^\frac{1}{3}\)

My answer is wrong. 

Here is my solution. 

^{\(x^\frac{1}{3} = y\)}

y = 4 / y 

y^2 = 4

y = 2

\(x^\frac{1}{3}=2\)

x = the cube root of 2

I hope this helped,

Gavin

1. 

7/90.

This is become 0.7... is tenfold of 0.07...

I just divided by 10 on 7/9. 

7/9 ÷ 10 = 7/90

The second one is a little more difficult. 

Let X equal the decimal number 

Equation 1:

\( X = 0.4\overline7\)

\(10X = 4.\overline7\)

Subtract equation (1) from equation (2)

10X - X = 4.3

9X=4.3

X = 43/90

I hope this helped, 

Gavin