When \(\sqrt[3]{-128}\) is simplified, the result is \(a\sqrt[3]{b}\) , where a is an integer, and b is a positive integer. If b is as small as possible, then what is a+b?
Hey there!
We need to factor out as much as we can in your cube root.
After we do, we have:
-4 times the cube root of 2.
I hope this helped,
Gavin.