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When \(\sqrt[3]{-128}\) is simplified, the result is \(a\sqrt[3]{b}\) , where a is an integer, and b is a positive integer. If b is as small as possible, then what is a+b?

ant101  Apr 29, 2018
 #1
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Hey there!

 

We need to factor out as much as we can in your cube root.

 

After we do, we have:

 

-4 times the cube root of 2.

 

I hope this helped,

 

Gavin. 

GYanggg  Apr 29, 2018

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