When \(\sqrt[3]{-128}\) is simplified, the result is \(a\sqrt[3]{b}\) , where a is an integer, and b is a positive integer. If b is as small as possible, then what is a+b?

ant101  Apr 29, 2018

Hey there!


We need to factor out as much as we can in your cube root.


After we do, we have:


-4 times the cube root of 2.


I hope this helped,



GYanggg  Apr 29, 2018

7 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.