hectictar

(g o f)( -2 )   =   g( f( -2 ) )

f( -2 )   =   | 3(-2) | - 10   =   | -6 | - 10   =   6 - 10   =   -4

g( -4 )   =   2(-4)³   =   2(-64)   =   -128

(g o f)( -2 )   =   g( f( -2 ) )   =   g( -4 )   =    -128

I get  -128 . Does that answer make sense to you? 

Hahaha!!!!  Thanks CPhill, I needed a laugh  

1.

I think this one is  A.  " A percent " .

2.

37.5% of the number of people surveyed   =   180

0.375  *  the number of people surveyed   =   180

the number of people surveyed   =   180 / 0.375    =    480

5  +  3.2n  -  6  -  4.8n

=   5  +  3.2n  +  -6  +  -4.8n

                                                  We can add numbers in any order.

=   5  +  -6  +  3.2n  +  -4.8n

=   (5  +  -6)  +  (3.2n  +  -4.8n)

=   (5  -  6)  +  (3.2n  -  4.8n)

=   (  -1  )  +  (  -1.6n  )

=   -1  -  1.6n

You meant to put  m  or you meant to put  x  ? 

7/18 %   =   (7/18) / 100   =   7/18  *  1/100   =   7 / 1800

7/18 ​%  of a quantity is equal to   7/1800  of the​ quantity.

The question is...

The number of medium-sized jerseys out of the total number of jerseys is what out of 100 ?

number of medium-sized jerseys / total number of jerseys   =   x / 100

14 / 20   =   x / 100

100 * 14 / 20   =   x

70  =  x

70 percent of the jerseys are medium-sized jerseys. 

(a)  Yes. m∠ACB  =  m∠ECD since they are vertical angles, and  m∠ABC  =  m∠CDE . So by the AA congruency postulate,  △ABC ~ △EDC  .

(b)  Since  △ABC ~ △EDC  ....

DE / DC   =   BA / BC

 32 / 22    =   BA / 100     Multiply both sides of the equation by 100 .

145.45     ≈   BA

The width of the river is approximately  145.45 ft.

Also...usually these confuse me, so I have to do it like this...

N_t+1   =   2.5N_t

N₇₊₁   =   2.5N₇   =   2.5(16,400 )   =   N₈

N₈₊₁   =   2.5N₈   =   2.5( 2.5(16,400 ) )   =   N₉

N₉₊₁   =   2.5N₉   =   2.5( 2.5( 2.5(16,400 ) ) )   =   N₁₀   =   2.5³ * 16,400   =   256,250