hectictar

Thank you! It helped that I read MaxWong's answer to it the other day :)

Ohhh!  I came across a few LOST DOG signs....I guess they were just old and needed to be taken down? 

.......

I bet whoever that flower brain is would would really really appreciate that 

Maybe this will help:

sum of tetrahedron edges = red line + orange line + yellow line + green line + blue line + purple line

red line = \(\sqrt{3^2+2^2}=\sqrt{13}\)

orange line = \(\sqrt{3^2+4^2}=\sqrt{25}=5\)

yellow line = \(\sqrt{2^2+4^2}=\sqrt{20}=2\sqrt5\)

sum of tetrahedron edges = \(\sqrt{13}+5+2\sqrt5+3+2+4=14+\sqrt{13}+2\sqrt{5} \approx 22.078\)

Hmmmmm..I think that yours is a much better approach than mine..

Mine does assume that you can cut a piece and glue it on. Why not cut off a bunch of pieces and use them all to make a box..instead of throwing paper away. And on mine, for the four littler prisms, you could use some of the old paper that you cut off from other prisms to make the bases.

\(\frac14\div\frac58=\frac14\times\frac85=\frac{1\times8}{4\times5}=\frac8{20}=\frac25\)

I can try to explain my answer more thoroughly 

Here I have shaded in the middle triangle and labeled points A, B, and C.

The yellow section is half of the area of the circle MINUS the area of the gray triangle.

area of the circle = π * radius²

area of the circle = π * (4)²

area of the circle = 16π   sq. cm.

area of the gray triangle = (1/2) * base * height

the base = 8 and the height = AO

Point O cuts line CB in half..OB = (1/2) * CB

Point A cuts line OB in half..AO = (1/2) * OB

We know line CB = 8....so OB = (1/2) * 8 = 4... and.. AO = (1/2) * 4 = 2

So, the height = 2,  and the base = 8.

area of the gray triangle = (1/2) * 8 * 2

area of the gray triangle = 8   sq. cm.

The yellow section is half of 16π MINUS 8 sq. cm.

yellow section = (1/2) * 16π - 8

yellow section = 8π - 8   sq. cm.

Solve the equation for x, and then set the denominator = 0. Whatever y value makes the denominator = 0 is not attainable.

y = \(\frac{1-x}{2x+3}\)               Multiply both sides by (2x + 3)

y(2x + 3) = 1 - x     Distribute
2xy + 3y = 1 - x     Add x to both sides.
2xy + 3y + x = 1    Subtract 3y from both sides.

2xy + x = 1 - 3y     Factor out an x on the left side.
x(2y + 1) = 1 - 3y   Divide both sides by 2y + 1

x = \(\frac{1-3y}{2y+1}\)

Now set the denominator = 0 and solve for y.

2y + 1 = 0

2y = -1

y = \( -\frac12 \)

Therefore, the value of y that is not attainable is \( -\frac12 \)

There is only one correct way to interpret a math problem. You probably just made a careless mistake somewhere. For this, just remember to work on the inntermost brackets each step, and multiplication/division comes before addition/subtraction. 

-11 + 2(-5 - 6(-1 - 3(2 - 7) ) )

-11 + 2(-5 - 6(-1 - 3(-5) ) )

-11 + 2(-5 - 6(-1 - 3(-5) ) )

-11 + 2(-5 - 6(-1 - -15) )

-11 + 2(-5 - 6(14) )

-11 + 2(-5 - 6(14) )

-11 + 2(-5 - 84)

-11 + 2(-89)

-11 + 2(-89)

-11 - 178

-189

Ah something is slightly off..the diagonal must be longer than the length of the sides...!

I think you forgot a one zero at the end...it should be

\(c=\sqrt{28800}=120\sqrt2 \approx 169.706\)      (meters)