hi1234

equation of a line in standard form is:  Ax + By + C = 0
x stands for x-intercept and y stands for y-intercept
the equation of a line in y-intercept form is y=mx+b

slope(m)= 8
y-intercept= (0,14)
Plugging this into the equation y=mx+b, we have:

y=8x+14   → change this into standard from by moving "y" to the other side
0=8x+y+14

substitute (0) for y to solve for x

0=8x+14

-14=8x

-14/8=x

-7/4=x

therefore, the x-intercept of the line is -7/4

thank you, but is there a way of solving it without using the quadratic formula?

The formula for the area of a Trapezoid is : A=( a+b )h/2 (a+b are the numerators)

a and b are the bases, so we can say a=6 and b=22

h=4 (height)

A= (6+22)4 / 2

A= 28*4/2

A=28 * 2 

A=56in²

if im incorrect someone please correct me!

-4(x + 4) > x + 7 + 8x + 21

-4x-16 > 9x+28

-4x- 9x >28+ 16

-13x >44

x < -44/13

(a + 2)(3a² + 2)(a - 12) →expand the first 2 brackets using distributive property

= (3a³+2a+6a²+4)(a-12)  → use distributive property again to multiply these 2 brackets together

=3a⁴-36a³+2a²-24a+6a³-72a²+4a-48 →group the like terms together, (the exponents)

=3a⁴-30a³-70a²-20a-48 → answer