math

ax^2 + bx + c = 0

Use the quadratic formula, \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

thank you, but is there a way of solving it without using the quadratic formula?

sqrt ( 2085136k^4)  = 1444k^2

sqrt ( 4100625)   = 2025

Note that  2 (1444k^2) (2025)   = 5848200k^2

So

(1444k^2 - 2025)^2   = 0

Take  the sqrt

1444k^2  -  2025   = 0

1444k^2   = 2025           take  both sqrts 

38k  = 45                    38k   = -45

k = 45 / 38                  k = -45/38